k=-6/7 solved by cross multiplying.
Answer:
<1 ,1>..., square root of two
Step-by-step explanation:
Component of vector PQ...,
; Q - P...where you subtract the x coordinate of Q by the x coordinate of P and the same for the y coordinate
; <(6-5),(9-8)>
; < 1,1 >
And the magnitude of PQ...,
;square root of( 1^2 + 1^2 )
;square root of 2
Answer: b=13, t=29
Step-by-step explanation:
Substituting the first equation into the second,

Since there is nothing on the left side of the equation besides the absolute value, you have to take 6m out of the absolute value and create 2 separate equations. These 2 equation will be 6m = 42 and 6m = -42.
You solve the equations normally:
6m = 42 6m = -42 (inverse to get m by itself, do on both sides)
/6 /6 /6 /6
m = 7 m = -7
The answer is a solution set:
[7, -7]