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4 years ago

Please help. Thank you

Mathematics

1 answer:

Inessa [10]4 years ago

6 0

Given:

$PQRS\sim TUVW$

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

$PQRS\sim TUVW$

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

$k=\dfrac{VW}{RS}$

$k=\dfrac{25}{35}$

$k=\dfrac{5}{7}$

Therefore, the scale factor from PQRS to TUVW is $k=\dfrac{5}{7}$ .

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What is the probability that a person who is older than 35 years has a hemoglobin level between 9 and 11

lora16 [44]

Answer:

1. The probability that a person who is older than 35 years has a hemoglobin level between 9 and 11 is 0.284.

2. The probability that a person who is older than 35 years has a hemoglobin level of 9 and above is 0.531.

Step-by-step explanation:

Let the number of person who is older than 35 years has a hemoglobin level between 9 and 11 be x.

From the given table it is clear that the total number of person who is older than 35 years is 162.

$76+x+40=162$

$x+116=162$

$x=162-116$

$x=46$

The number of person who is older than 35 years has a hemoglobin level between 9 and 11 is 46.

The probability that a person who is older than 35 years has a hemoglobin level between 9 and 11 is

$P=\frac{\text{Person who is older than 35 years has a hemoglobin level between 9 and 11}}{\text{Person who is older than 35 years}}$

$P=\frac{46}{162}\approx 0.284$

The probability that a person who is older than 35 years has a hemoglobin level between 9 and 11 is 0.284.

Person who is older than 35 years has a hemoglobin level of 9 and above is

$46+40=86$

The probability that a person who is older than 35 years has a hemoglobin level of 9 and above is

$P=\frac{\text{Person who is older than 35 years has a hemoglobin level of 9 and above}}{\text{Person who is older than 35 years}}$

$P=\frac{86}{162}\approx 0.531$

The probability that a person who is older than 35 years has a hemoglobin level of 9 and above is 0.531.

4 0

3 years ago

Gina started with the circle (x−2)2+y2=16. She translated it 4 units left and 1 unit down. Then she reduced the radius by 1 unit

olchik [2.2K]

Answer:

(x + 2)² + (y + 1)² = 9

Step-by-step explanation:

Gina started with a circle with the given equation as,

(x - 2)² + (y - 0)² = 16

Since, standard equation of a circle is,

(x - a)² + (y - b)² = r²

Here (a, b) is the center of the circle and 'r' is the radius.

Therefore, from the given equation of the circle,

Center of the circle → (2, 0)

Radius of the circle → √16 = 4 units

She translated this circle 4 units left and 1 unit down.

Rule for the new center after translation will be,

(x, y) → (x - 4, y - 1)

(2, 0) → (2 - 4, 0 - 1)

→ (-2, -1)

Coordinates of the new center → (-2, -1)

Then she reduced the radius by 1 units.

Therefore, radius of the new circle = 4 - 1 = 3 units

Now we substitute these values in the standard equation of the circle to get the equation of the new circle.

(x + 2)² + (y + 1)² = 3²

(x + 2)² + (y + 1)² = 9

5 0

3 years ago

Bought computer for $500. Marked down $50. Plus a 25% discount off original price. What is the original price?

andriy [413]

So 500+50=550

550=25-100=75%

550=75%
multiply both sdies yb 4
2200=300%
divide by 3
733.333=100%

the origonal price=$733.33

8 0

3 years ago

Read 2 more answers

What statements are always true for a square

bagirrra123 [75]

A square's sides are always all congruent. A square's angles are always all congruent. The opposite sides of a square are always parallel.

6 0

3 years ago

0.0006577 in scientific notation

Shalnov [3]

Answer:

= 6.577 × 10^-4

Step-by-step explanation:

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is a.

Count how many places you moved the decimal point. This number is b.

If you moved the decimal to the left b is positive.

If you moved the decimal to the right b is negative.

If you did not need to move the decimal b = 0.

Write your scientific notation number as a x 10^b and read it as "a times 10 to the power of b."

Remove trailing 0's only if they were originally to the left of the decimal point.

Hope this helped

4 0

3 years ago

Read 2 more answers