Question

Please i need to know if im correct with these questions

Answer 1

Answer: No Solution

Step-by-step explanation:

ln x - ln (x + 2) = 4             restrictions: x > 0  and  x + 2 > 0   →    x > 0

ln $(\frac{x}{x + 2})$ = 4

$(\frac{x}{x + 2})$ = e⁴

x = e⁴ (x + 2)

x = 54.5982 (x + 2)

x = 54.5982x + 109.1964

- 53.5982x = 109.1964

x = $\frac{109.1964}{-53.5982}$

x = -2.0373

-2.0373 is not greater than 0 so is not valid

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Answer: 2.1972

Step-by-step explanation:

eˣ = 9

ln eˣ = ln 9

   x = ln 9

   x ≈ 2.1972

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Answer: $\frac{3}{2}$

Step-by-step explanation:

log₂ (3x - 4) = -1

        3x - 4 = 2⁻¹

         3x - 4 = $\frac{1}{2}$

              +4   +4

          3x     = $4\frac{1}{2}$

          3x     = $\frac{9}{2}$

          $\frac{3x}{3} = \frac{9}{2} * \frac{1}{3}$

            x = $\frac{3}{2}$

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Answer: 1.117519

Step-by-step explanation:

in the calculator, type in 1 ÷ 9.

Then hit the eˣ button.

 e¹⁾⁹

= e°¹¹¹¹¹¹

= 1.117519

rounded to 6 decimal places: 1.117519