The formula F = ma shows the relationship between force, mass, and acceleration. Solve this formula for a.

How

andrey2020 [161]

Answer: 7800

Step-by-step explanation:

As English alphabet has 26 letters.

So , Choices for First character in the code = 26

The choices for digits = 10 (From 0 to 9)

So , choices for second character = 10 (Middle two characters must be numbers)

choices for third character = 10 (Middle two characters must be numbers)

Choices for last character = 3 (the last character must be a 1, 3, or 7)

By Fundamental principle of counting , the total number of four character codes can be generated =

(Choices for First character)x (choices for digits) x(choices for digits) x(Choices for last character)

= (26) (10)(10)(3) =7800

Hence, the total number of character codes can be generated= 7800

6 0

3 years ago

3. Armen los siguientes prismas a partir de los que construyeron con su material recor

KiRa [710]

Answer:

can you translate to english

Step-by-step explanation:

I can't understand

6 0

3 years ago

What # × what # equals 2079

vesna_86 [32]

You can divide it by 9 and get 231 so 231 times 9 equals 2079

7 0

3 years ago

Read 2 more answers

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

2x-5y=10 ;what is the x intercept, what is the y intercept, what is the slope?

creativ13 [48]

First we put the equation in y = mx + b form where m is ur slope and b is ur y int.

2x - 5y = 10
-5y = -2x + 10
y = 2/5x - 2.......so ur slope is 2/5 and ur y int is (0,-2) <==

to find ur x int, sub in 0 for y and solve for x
2x - 5y = 10
2x - 5(0) = 10
2x = 10
x = 10/2
x = 5......and ur x int is (5,0) <==

another way to find the y int is to sub in 0 for x and solve for y...but u might as well solve it by putting it in y = mx + b form because that way u have ur slope as well.

4 0

3 years ago

Read 2 more answers