3 years ago

Beth wants to buy a gaming system for 220$.

1 answer:

3 0

3 I think lol
- Samuel

Though, I’m not sure

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sukhopar [10]

$\left[\begin{array}{cc}Juice&Water\\1&3\\2&6\\3&9\\4&12\\\end{array}\right]$

$w=3j$
$36=3j$
$j=\frac{36}{3}=12cups$

3 0

3 years ago

zheka24 [161]

Answer:

its 5

Step-by-step explanation:

cause 2 divided by 30is 15 minus 10 its 5

4 0

3 years ago

GrogVix [38]

Use the method pemdas and you get x=28

7 0

4 years ago

Zigmanuir [339]

Answer:

$P(E \cup F)=P(E)+P(F)$ .

Step-by-step explanation:

Given the statement

If $P(E)+P(F)=P(E \cup F)+P(E \cap F)$ , then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

$P(E \cup F)=P(E)+P(F)$ .

3 0

4 years ago

Mila [183]

Answer my question and I'll answer yours!!!

4 0

3 years ago