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Dafna1 [17]
3 years ago
9

Is 1/2 an irrational number?

Mathematics
1 answer:
Vinvika [58]3 years ago
4 0

Answer:

Yes, 1/2 is a irrational number

Step-by-step explanation:

This is the answer because (Google research):

A number is rational if we can write it as a fraction where the numerator and denominator are both integers. However, numbers like 1/2, 46485928/2628242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

Hope this helps!

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Inessa [10]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ To find the mean, add up all the numbers and divide by the amount of numbers there are. To find the range, subtract the highest number by the  lowest number in the data set.

2. Mean = 35  Range = 78

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6. Mean = 55  Range = 83

7. Mean = 61   Range = 53

8. Mean = 60  Range = 75

9. Mean = 50  Range = 76

10. Mean = 50  Range = 81

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

7 0
3 years ago
Can someone help please
xxMikexx [17]
D- It is an enlargement with a scale factor greater than 1.

From the pre-image to the image, the scale factor is 3.
5 0
3 years ago
Three students were given the expression shown to simplify<br><br> 1-8(10x-3)​
madreJ [45]

Answer:

-70x + 21

Step-by-step explanation:

1-8(10x-3)

-7(10x-3)

Use distributive property

-70x + 21

(This is how we learned to do it in my school)

6 0
3 years ago
Read 2 more answers
Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9
natulia [17]
Parameterize C by

\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle

where 0\le t\le\pi. Then the line integral is

\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt
=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt
=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt

Take u=\cos t, then

=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du
=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du
=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du
=54
6 0
3 years ago
I am having trouble with helping a friend on math and the question is
Archy [21]
In simplest form it should be 5/7
6 0
2 years ago
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