First, you need to find the derivative of this function. This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.
f'(x)=3x^2-3
Now, set this function equal to 0 to find x-values of the relative max and min.
0=3x^2-3
0=3(x^2-1)
0=3(x+1)(x-1)
x=-1, 1
To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each. We will use -2, 0, 2.
f'(-2)=3(-2)^2-3=3(4)-3=12-3=9
f'(0)=3(0)^2-3=3(0)-3=0-3=-3
f'(2)=3(2)^2=3(4)-3=12-3=9
We examine the sign changes to determine whether it is a max or a min. If the sign goes from + to -, then it is a maximum. If it goes from - to +, it is a minimum. Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.
To determine the values of the relative max and min, plug in the x-values to f(x).
f(-1)=(-1)^3-3(-1)+1=-1+3+1=3
f(1)=(1)^3-3(1)+1=1-3+1=-1
Hope this helps!!
Im pretty sure it'll be 400
Because if you take 20min/3pag then you times it by 60min it would equal 400. Hope I helped
Answer:
B is correct
Step-by-step explanation:
The person is mentioned is Phil. His amount of money and number of miles are proportionally related (Clark's amount of money and number of miles are not proportionally related due to initial donation)
For Phil, y = ax is his model.
Look into the graph, we can see there is a point where y = 30 and x = 4.
Then rate = 30/4 = 7.5
Answer:
y = 2/3 x - 2.
Step-by-step explanation:
The slope of the line = rise/run = 2/3 and the y-intercept is at y = -2.
The equation is y = mx + c where the slope m = 2/3 and c = -2.
