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krok68 [10]
3 years ago
15

Adamson Corporation is considering four average-risk projects with the following costs and rates of return:

Business
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

a. Cost of debt = Interest * (1 - Tax rate)

= 10%*(1 - 0.30)

= 7%

Cost of preferred stock = Dividend/ Issue price

= 5/48

= 10.42%

Cost of common stock (Cost of retained earnings) = (D1/P0) + g

= (4/33) + 0.07

= 0.12 + 0.07

= 0.19

= 19%

b. Fund                         Cost        Weight       Cost * Weight

Debt                           7%          0.15                 1.05%

Preferred stock        10.42%     0.10                1.042%

Retained earnings     19%         0.75               <u>14.25%</u>

WACC                                                               <u>16.342%</u>

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Forensic Scientists are part of the career pathway known as
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Maria is a hard-working college sophomore. One Sunday, she decides to work nonstop until she has answered 100 practice problems
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Answer:

The correct answers are:

i. The marginal, or additional, gain from Maria’s first hour of work, from 8:00 AM to 9:00 AM, is <u>  40  </u> problems.

ii. The marginal gain from Maria’s third hour of work, from 10:00 AM to 11:00 AM, is <u>   20   </u> problems

iii. 2 hours working on problems, 2 hours reading (c)

Explanation:

i. The marginal gain from 8:00 AM to 9:00 AM is calculated thus:

work done at 8:00 AM = 0 problems

Work done at 9:00 AM = 40 problems

Marginal gain = (Work done at 9:00 AM) - (work done at 8:00) = 40 - 0 = 40 problems

ii. work done at 10:00 AM = 70 problems

work done at 11:00 AM = 90 problems

Marginal gain = 90 - 70 = 20 problems

iii. To get the best exam score, the most number of problems possible in total must be answered within the 4-hour period, and this is determined as follows:

we are told that Maria gets tired as time progresses and the number of questions answered reduces we notice the following numbers of questions answered in each hour:

8:00 AM to 9:00 AM = 40 - 0 = 40 problems (hour 1)

9:00 AM to 10:00 AM = 70 - 40 = 30 problems (hour 2)

10:00 AM to 11:00 AM = 90 - 70 = 20 problems (hour 3)

11:00 AM to Noon = 100 - 90 = 10 problems (hour 4)

Also, we are told that;

1 hour of reading = 25 problems

Comparing the reading and solving problems, we see that the number of problems solved in hour-1 and hour-2  (40 and 30 respectively) are more than the equivalent number of problems solved in reading for 1 hour, while hour-3 and hour-4 (20 and 10 respectively), have lesser equivalent number of problems each, than reading for one hour. Therefore to make the most out of the 4 hours, Maria will spend the first 2 hours solving problems and the next two hours reading, giving a total of: 40 + 30 + 25 + 25 = 120 problems solved.

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