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Paul [167]
2 years ago
14

The rectangular floor of a classroom is 32 feet in length and 40 feet in width. A scale drawing of the floor has a length of 8 i

nches. What is the ares, in square inches,of the floor in the scale drawing
Mathematics
1 answer:
omeli [17]2 years ago
7 0
82 inches is the correct answer
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A.45<br> B.30<br> C.90<br> D.180<br> E.40<br> F.55<br> G.130<br> H.50
brilliants [131]

Answer:

m<4=40

Step-by-step explanation:

Supplementary angles form 180 degrees

m<3 is vertical to the 50 degree angle which is equal.

so. m<3=50

m<5=90

90+50=140

180-140=40

m<4=40

4 0
2 years ago
A person is trapped in a burning building 60feet off the ground. A rescuer has a 70 foot ladder, but for safety purposes the lad
Neko [114]
Yes because, if the building is 60 ft from the ground and the ladder is 70 ft,shouldn’t it escalate an extra 10 ft because this is technically an emergency and it can be considered to be used as a reason for safety purposes, if I’m not mistaken
3 0
2 years ago
Find the equation of the line that passes through the following two points: (3, -7) and (7, 2)
Wittaler [7]

Answer:

y=\frac{9}{4}x-\frac{55}{4}

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

Given points: (3, -7), (7, 2)

(3, -7) = (x1, y1)

(7, 2) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

\frac{2-(-7)}{7-3}

Simplify:

2 - (-7) = 2 + 7 = 9

7 - 3 = 4

\frac{9}{4}

The slope is \frac{9}{4}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:

2=\frac{9}{4}(7)+b

2=\frac{63}{4}+b

-\frac{55}{4} =b

The y-intercept is -\frac{55}{4}.

Now that we know the slope and the y-intercept, we can write the equation:

y=\frac{9}{4}x-\frac{55}{4}

6 0
3 years ago
Which row operation will trangularize this matrix?
Nadya [2.5K]

\left[\begin{array}{ccc}1&0&1\\0&0&1\\2&0&1\end{array}\right|\left\begin{array}{ccc}1\\6\\10\end{array}\right] \xrightarrow{-2R_1+R_3}\left[\begin{array}{ccc}1&0&1\\0&0&1\\0&0&-1\end{array}\right|\left\begin{array}{ccc}1\\6\\8\end{array}\right]\\\\Answer:\ C.\ -2R_1+R_3

8 0
2 years ago
Read 2 more answers
How to find algebraic expressions using a table of values
Makovka662 [10]
I think that the answers is b
6 0
3 years ago
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