Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Answer:
I don't know what the options are, but to solve t/8 = 2, you have to multiply by 8.
Hope this helps :)
Answer:
y = 5
Step-by-step explanation:
That "+5" elevates the graph of this cosine function 5 units above the x axis, and thus the "midline" you wanted is y = 5.
a.
<K = <M = 50 ...Opposite angels are congruent
<K + <L = 180...Consecutive angles are supplementary
50 + <L = 180 so <L = 180 - 50 = 130
<L = <N = 130...Opposite angels are congruent
50 + <N = 180 so <N = 180 - 50 = 130
b.
MN = LK = 7...Opposite sides are congruent
KN = LM = 10...Opposite sides are congruent
Volume of a sphere: V=(4/3)πr³
V1=(4/3)π10³
V2=(4/3)π5³
difference: (4/3)π10³-(4/3)π5³=(4/3)π875=3665
the answer is B.<span />
