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2 years ago

13

BRAINLEST!!!Several students made comments about this image.

2 answers:

Lerok [7]2 years ago

6 0

The third comment is the true one: "If I know the measures of angles C and B, I can find the measures of A and D."
This is because you can use the angle B to find angle A by subtracting it from 180, and you can find angle D by adding together C and B and subtracting that from 180.
I hope this helps!

Lostsunrise [7]2 years ago

6 0

The third statement is true

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

serg [7]

Answer:

Step-by-step explanation:

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2 years ago

What would my answer be?

Svetllana [295]

Since triangle is isosceles, that means that unknown angles are equal. 180-72=108
108:2=54
So you’re answer would be: 54 degrees.

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2 years ago

Tell whether the ratios form a proportion. 14:8 and 28:10

Dima020 [189]

Answer:

no

Step-by-step explanation:

14:8 = 14/8 = 7/4

28:10 = 28/10 = 14/5

Since the fractions are not equal, it is not a proportion.

Answer: no

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1 year ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

2 years ago

Please answer this question

gladu [14]

Answer:

A

hope that helped <3

8 0

2 years ago

Read 2 more answers