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Sergeeva-Olga [200]
3 years ago
15

Please help me I will give you the brain thing and extra points. (image below) 27/30

Mathematics
1 answer:
baherus [9]3 years ago
7 0
The answer of this question is C
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Jose now has $500. how much would he have after 6 years if he leaves it invested at 5.5% with annual compounding?
Vesnalui [34]
Amount after 6 years = 500(1 + 0.055)^6 = $689.42  Answer
6 0
3 years ago
Which of the following is two-dimensional and infinitely large?
Sergeeva-Olga [200]

Answer:

a plane

Step-by-step explanation:

A plane because it is two-dimensional and infinitely large.    

5 0
3 years ago
Which congruence theorems can be used to prove ΔEFG ≅ ΔJHG? Select two options.
Aleks04 [339]

Answer:

AAS , ASA.

Step-by-step explanation:

2 angles and  one side are congruent.

2 pairs of alternate angles are equal or you could have 1 pair of alternate and  vertical angles equal.

6 0
4 years ago
Read 2 more answers
How to solve (s + 5)(s - 5)
m_a_m_a [10]
(s+5)(s-5)=s^2-25

Here, we want to solve an expansion

To get this, we simply multiply the terms in the first bracket with the terms in the second, before we proceed to collect like terms

We have this as follows;

\begin{gathered} (s+5)(s-5)\text{ = s(s-5)+5(s-5)} \\ =s^2-5s+5s-25 \\ =s^2-25 \end{gathered}

7 0
1 year ago
In the diagram below, O is circumscribed about quadrilateral DEFG. What is
Nimfa-mama [501]

Since O is circumscribed about quadrilateral DEFG, the value of x is equal to: D. 68°.

<h3>What is a supplementary angle?</h3>

A supplementary angle can be defined as two (2) angles or arc whose sum is always equal to 180 degrees. Mathematically, a supplementary angle can be calculated as follows:

Q + R = 180°.

In Geometry, the opposite angles of any cyclic quadrilateral that is inscribed inside a circle always form a supplementary angle. Thus, we would determine the value of x by using the mathematical expression above:

x + 112° = 180°

x = 180° - 112°

x = 68°

Read more on supplementary angle here: brainly.com/question/12542846

#SPJ1

8 0
2 years ago
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