50 bro i think i’m just trynna get my answers
Number 1 would the last option, but I’m not sure about number 2
11x-22=-11x-22
11x+11x=-22+22
22x=0
x=0/22
x=0
Then the answer is option B
That is a very good question....
Look Grank
you know that:
confidence interval = mean +or- Margin of Error
and
Margin of Error = (z)*(standard deviation) / (sqrt of n)
where n is the number of sample records
So we need to calculate z-value firstly
It says: "<span>we want 90% confidence"
So that:
</span>
<span>confidence90% corresponds to z-value of 1.645
Plug that into our formula of </span><span>Margin of Error:
</span>Margin of Error = (1.645)*(22) / (sqrt of n)
"The sample mean is within 2.7 lb of the population mean" means that Margin of Error is 2.7
<span>Margin of Error:
</span>2.7 = (1.645)*(22) / (sqrt of n)
Now solve for n:
n=179.66~180
SO that 180<span> women must be randomly selected to estimate the mean weight of women in one age group.</span>
