Given:
Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.
To find:
The integers
.
Solution:
Let the smaller even integer be x.
So, larger even integer is x+2 because they are consecutive even integers.
Seven times the smaller integer = 7x
-300 minus 4 times the larger integer = -300-4(x+2)
Now,
Divide both sides by 11.
So, the smaller even integer is -28.
So, the larger even integer is -26.
<h3>
Answer: 2/3</h3>
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Explanation:
set A = dice values greater than 4 = {5,6}
set B = dice values 4 or less = {1,2,3,4}
Sets A and B are considered complementary because one or the other must happen. You must either roll something larger than 4 (set A) or you must roll something from set B.
There are 4 items in set B out of 6 possible outcomes. That leads us to the answer 4/6 = 2/3
Answer:
7x is your answer
I really hope this helps
Step-by-step explanation:
please like if right :)
These are exponents. To solve an exponent you need to multiply the base it self how many times its says in the power.
a²
a = base
2 = power
5³ = 5 × 5 × 5 = 125
5³ = 125
4³ = 4 × 4 × 4 = 64
4³ = 64
