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Bess [88]
3 years ago
10

Solve 4X^2+7 = 8X +4 by using the quadratic formula

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

(1.5,0)

(.5,0)

Step-by-step explanation:

Quadratic formula below

We first need to move everything to one side of the equation

4x²-8x+3=0

Then plug everything in

(8±√(-8²-4*4*3))/(2*4)

(8±√16)/8

To calculate the ± we need to do when where it's adding and then negative

we have

(8+4)/8=3/2

and hten

(8-4)/8=1/2

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erastovalidia [21]

Answer:

$11.40×$3=$34.2

This the price of the stapler

3 0
3 years ago
Can you pleases help me with 13 and 14 thank you
Anit [1.1K]
13. (24, 8); because the rule is: y=x÷3
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3 years ago
The point (-1,4)is translated five units right and three units down.which rule describes the translation
xz_007 [3.2K]

Answer:

(x, y ) → (x + 5, y - 3 )

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5 units right means add 5 to the x- coordinate

3 units down means subtract 3 from the y- coordinate

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3 years ago
Please help me find large & smaller angle
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8 0
4 years ago
4. If 100.0g of nitrogen gas (N2) is reacted with 100.0g of hydrogen gas (H2) to form NH3. What are the limiting and excess reac
alexandr1967 [171]

Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have

100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂

Hydrogen (H) has a molar mass of about 1.008 g/mol, so

100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂

In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have

3.570 • 3 ≈ 10.71

so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.

(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.

(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.

(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or

7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃

8 0
3 years ago
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