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Anettt [7]
4 years ago
14

When do you use a solid line for graphing a linear inequality?

Mathematics
1 answer:
g100num [7]4 years ago
4 0

Answer: You use it to represent that the equation your graphing is either greater than or equal too or less than or equal too

Step-by-step explanation:

A dotted line is there to represent that the equation your graphing is either grater than or less than

So the solid line represents the same thing, except that they both have a possibility of being equal too which is why the line is solid.

I hope this helps!

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Alborosie

The variable 'T' equals -20.

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3 years ago
What is it called when a sea bird lands on a channel maker
murzikaleks [220]

Answer:

This question is actually a riddle. The answer to this riddle is, "Buoy meets gull."

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The length of a rectangle is 22 centimeters and the width is
nataly862011 [7]

Answer:

78cm

Step-by-step explanation:

L₁/W₁ = L₂/W₂

22/4 = L₂/6

5.5*6=L₂

L₂=33cm

Perimeter of rectangle = 2L+2W

=2(33)+2(6)

=66+12

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3 years ago
Please help me with problems one through four and show work. (Preferably on paper)
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Step-by-step explanation:

I hope you can understand my steps and hope you all the best in matematic. There are various type of calculation, i try my best to do in easy way

8 0
3 years ago
when the polynomial f(x) is divided by (x-2) the remainder is 4, and when it is divided by (x-3) the remainder is 7. Given that
natima [27]

f(x)=(x-2)(x-3)Q(x)+ax+b

Recall the polynomial remainder theorem: the remainder upon dividing a polynomial p(x) by x-c is equal to p(c). This means that f(2)=4 and f(3)=7, which tell us

4=2a+b

7=3a+b

From here we can solve for a,b:

4=2a+b\implies b=4-2a

7=3a+b=3a+(4-2a)\implies a=3\implies b=-2

so that

f(x)=(x-2)(x-3)Q(x)+3x-2

Now,

\dfrac{f(x)}{(x-2)(x-3)}=Q(x)+\dfrac{3x-2}{(x-2)(x-3)}

so the remainder upon dividing f(x) by (x-2)(x-3) is 3x-2.

Next, if f is a cubic function, then Q(x) is a linear polynomial that can be written as Q(x)=cx-d. The coefficient of x^3 in f(x) is 1 (unity), so that expanding f(x) gives us

f(x)=(x-2)(x-3)(cx-d)+3x-2

f(x)=(cx^3-(5c+d)x^2+(6c+5d)x-6d)+3x-2

f(x)=cx^3-(5c+d)x^2+(6c+5d+3)x-(6d+2)

\implies c=1

and we also have that f(1)=1, so that

1=1-(5+d)+(6+5d+3)-(6d+2)

\implies2d=2\implies d=1

so that

Q(x)=x-1

4 0
3 years ago
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