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Flauer [41]
3 years ago
12

4x^3(5x) = what, will mark brainliest

Mathematics
2 answers:
Rzqust [24]3 years ago
6 0

Answer:

25

Step-by-step explanation:

Tomtit [17]3 years ago
4 0
Answer: 25x^4
Hope you have luck with this answer
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N/8 = 11/5<br> What does n equal?
Goshia [24]

\dfrac{n}{8}=\dfrac{11}{5}\\\\ 5n=88\\\\ n=\dfrac{88}{5}

6 0
3 years ago
Read 2 more answers
1. Use the formula d=rt. FInd the rate when d=13 mi and t=3 h.
lakkis [162]
1.
d = rt
13 = r*3
r = 13/3

2.
v = r + at
a = (v-r)/t
3 0
3 years ago
Nevermind anyone know this answer???
Semenov [28]

Answer:

x = 6

Step-by-step explanation:

for SPECIAL RIGHT TRIANGLES specifically a 30°-60°-90° triangle.

The longest side is the hypotenuse. The longest side is twice the shortest side. Or the other way around, the shortest side is half the longest side.

Here the longest side (hypotenuse) is 12, so the shortest side is 6.

Also, since you seem to be trying to get this subject.

The long leg is the short leg× sqroot3.

OR the short leg is the long leg ÷ sqroot3. If you end up with a sqroot on the bottom of a fraction, you can't leave it like that. Times top and bottom by sqroot3/sqroot3 to fix it.

4 0
2 years ago
What is estimate of 1/8+1/4=
Cloud [144]
3/8
1/4=2/8 so 1/8 + 2/8 is 3/8
5 0
3 years ago
Read 2 more answers
The average price of gas in 2000 was $1.57 per gallon, and $2.30 in 2005. What is the rate of change for each year between 2000
KATRIN_1 [288]

Answer: $ 0.146 per year.

Step-by-step explanation:

Given: Average price of gas in 2000 = $1.57 per gallon

Average price of gas in 2005 = $2.30 per gallon

The rate of change for each year between 2000 to 2005

= \dfrac{\text{Change in price}}{\text{Change in time}}

=\dfrac{\text{Price in 2005- Price in 2000}}{2005-2000}\\\\=\dfrac{2.30-1.57}{5}\\\\=\dfrac{0.73}{5}=0.146

Hence, the rate of change for each year between 2000 to 2005 is $ 0.146 per year.

8 0
3 years ago
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