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nikklg [1K]
3 years ago
7

Someone pleasee help me with this freaking IXL.

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0
The answer is 1761 1/2 (1761.5 in decimal form)
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Write one hundred twenty-three and fourteen thousandths as a decimal number.
DochEvi [55]

Answer:

.12314

Step-by-step explanation:

3 0
3 years ago
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PLEASE HELP FAST QUESTION IN PHOTO WILL PICK <br> IF CORRECT
Elenna [48]
4 2/11 = 4.1818181

sqrt5 = 2.2360679......

3/16 = 0.1875

answer:
 3/16 terminates ( it only has 4 numbers)

4 2/11 don't terminate but keeps repeating 

sqrt5 doesn't terminate or repeat


5 0
3 years ago
What substitution should be used to rewrite 16(x3 + 1)2 – 22(x3 + 1) – 3 = 0 as a quadratic equation?
Vesna [10]

Answer:

  z = x^3 +1

Step-by-step explanation:

Noting the squared term, it makes sense to substitute for that term:

  z = x^3 +1

gives ...

  16z^2 -22z -3 = 0 . . . . the quadratic you want

_____

<em>Solutions derived from that substitution</em>

Factoring gives ...

  16z^2 -24z +2z -3 = 0

  8z(2z -3) +1(2z -3) = 0

  (8z +1)(2z -3) = 0

  z = -1/8  or  3/2

Then we can find x:

  x^3 +1 = -1/8

  x^3 = -9/8 . . . . . subtract 1

  x = (-1/2)∛9 . . . . . one of the real solutions

__

  x^3 +1 = 3/2

  x^3 = 1/2 = 4/8 . . . . . . subtract 1

  x = (1/2)∛4 . . . . . . the other real solution

The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.

7 0
3 years ago
Read 2 more answers
∠A and \angle B∠B are vertical angles. If m\angle A=(7x-27)^{\circ}∠A=(7x−27) ∘ and m\angle B=(3x+29)^{\circ}∠B=(3x+29) ∘ , then
mote1985 [20]

Answer:

x = 14

Step-by-step explanation:

Vertical angles are congruent , then

7x - 27 = 3x + 29 ( subtract 3x from both sides )

4x - 27 = 29 ( add 27 to both sides )

4x = 56 ( divide both sides by 4 )

x = 14

7 0
2 years ago
Find a center of mass of a thin plate of density delta equals 5δ=5 bounded by the lines y equals xy=x and x equals 0x=0 and the
kow [346]

Answer:

center of mass

X = \frac{my}{m} = \frac{28}{19}

Y = \frac{mx}{m} = \frac{872}{95}

Step-by-step explanation:

y = x and x = 0

parabola ; y = 20 - x^2

attached below is the detailed solution

M = \frac{152}{3}б

Mx =  \frac{6976}{15}б

My = \frac{224}{3}б

X = \frac{my}{m} = \frac{28}{19}

Y = \frac{mx}{m} = \frac{872}{95}

5 0
3 years ago
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