Question

Find a center of mass of a thin plate of density delta equals 5δ=5 bounded by the lines y equals xy=x and x equals 0x=0 and the parabola y equals 20 minus x squaredy=20−x2 in the first quadran

Answer 1

Answer:

center of mass

X = $\frac{my}{m} = \frac{28}{19}$

Y = $\frac{mx}{m} = \frac{872}{95}$

Step-by-step explanation:

y = x and x = 0

parabola ; y = 20 - x^2

attached below is the detailed solution

M = $\frac{152}{3}$б

Mx =  $\frac{6976}{15}$б

My = $\frac{224}{3}$б

X = $\frac{my}{m} = \frac{28}{19}$

Y = $\frac{mx}{m} = \frac{872}{95}$