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pav-90 [236]
3 years ago
13

Find a center of mass of a thin plate of density delta equals 5δ=5 bounded by the lines y equals xy=x and x equals 0x=0 and the

parabola y equals 20 minus x squaredy=20−x2 in the first quadran
Mathematics
1 answer:
kow [346]3 years ago
5 0

Answer:

center of mass

X = \frac{my}{m} = \frac{28}{19}

Y = \frac{mx}{m} = \frac{872}{95}

Step-by-step explanation:

y = x and x = 0

parabola ; y = 20 - x^2

attached below is the detailed solution

M = \frac{152}{3}б

Mx =  \frac{6976}{15}б

My = \frac{224}{3}б

X = \frac{my}{m} = \frac{28}{19}

Y = \frac{mx}{m} = \frac{872}{95}

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Step-by-step explanation:

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W = 50

5 0
3 years ago
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GenaCL600 [577]

Answer:

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Step-by-step explanation:

i hope this helped :)

8 0
3 years ago
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andriy [413]
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2 pi r
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6 0
3 years ago
Suppose that qequals30​, Lequals5​, and Kequals15 is a point on the production function qequals​f(L, ​K). Is it posssible for qe
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Answer:

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7 0
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Hope that helped.
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