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solmaris [256]
3 years ago
7

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into t

wo segments. In problem 1, you found the area of the smaller segment.)
Mathematics
1 answer:
almond37 [142]3 years ago
3 0
The answer to the problem "Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius" is A = (160/3 π + 16 √3) inches². Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.  
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Solve.<br><br> m - 15 = 20<br><br> m =
Fittoniya [83]

\text{Hello There!}

\text{We are going to need to isolate the variable}

m - 15 = 20

\text{Add 15 to both sides.}

\text{We do this because we need to perform inverse operations to find} \text{the value of the variable.}

m - 15 + 15 = 20 + 15 = 35

\fbox{Therefore, your answer is going to be 35.}

\rule{300}{1.5}

7 0
3 years ago
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How would you determine the axis of symmetry in order to graph x^2 = 8y^2.
Tanya [424]
The picture illustrates the definition. The point P is a typical point on the parabola so that its distance from the directrix, PQ, is equal to its distance from F, PF. The point marked V is special. It is on the perpendicular line from F to the directix. This line is called the axis of symmetry of the parabola or simply the axis of the parabola and the point V is called the vertex of the parabola. The vertex is the point on the parabola closest to the directrix.

Finding the equation of a parabola is quite difficult but under certain cicumstances we may easily find an equation. Let's place the focus and vertex along the y axis with the vertex at the origin. Suppose the focus is at (0,p). Then the directrix, being perpendicular to the axis, is a horizontal line and it must be p units away from V. The directrix then is the line y=-p. Consider a point P with coordinates (x,y) on the parabola and let Q be the point on the directrix such that the line through PQ is perpendicular to the directrix. The distance PF is equal to the distance PQ. Rather than use the distance formula (which involves square roots) we use the square of the distance formula since it is also true that PF2 = PQ2. We get

<span>(x-0)2+(y-p)2 = (y+p)2+(x-x)2. 
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Although we implied that p was positive in deriving the formula, things work exactly the same if p were negative. That is if the focus lies on the negative y axis and the directrix lies above the x axis the equation of the parabola is

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Another situation in which it is easy to find the equation of a parabola is when we place the focus on the x axis, the vertex at the origin and the directrix a vertical line parallel to the y axis. In this case, the equation of the parabola comes out to be

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Parabolas in standard positionIn this demonstration we show how changing the value of p changes the shape of the parabola. We also show the focus and the directrix. Initially, we have put the focus on the y axis. You can select on which axis the focus should lie. Also you may select positive or negative values of p. Initially, the values of p are positive. 

5 0
3 years ago
Write –0.825 as a fraction.
olga2289 [7]

Answer:

OK 825/1000 That is the answer.

8 0
3 years ago
Which equation models the problem?
morpeh [17]

Answer:

B=0.10x+2

Step-by-step

sponsor b is paying .10 x 52 pins + $2.  = 5.20 + 2 = 7.20

it isn’t  the 2 times 52

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and we have to consider the 52 pins as X

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Evaluate 16 - 4 ÷ 4 <br>a 3<br>b 2<br>c 5<br>d 15
Alenkasestr [34]
The answer is D. 15 plz give me brainliest answer
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