60 x 50 = 3000 meters.......
(5,24)
- The two areas are the same.
- To find the area, we multiply the side lengths. Y=area
Rectangle 1: side lengths 4 and (x+1)
y=4(x+1)= 4x+4
Rectangle 2: side lengths 3 and (2x-2)
y=3(2x-2)= 6x-6
- Since the two areas are same, we can conclude that
4x+4=6x-6
-2x=-10, x=5
- Since x is 5, we can plug it into the equations to find y.
Option 1 with rectangle 1: y=4(5)+4, y=24
Option 2 with rectangle 2: y=6(5)-5, y=24
I graphed the linear equation on desmos.
So first you want to convert both to have the same denominator.
5 1/2 - 3 3/4
To:
5 2/4 - 3 3/4
Now, to make it easier for me, I would convert both to an improper fraction.
5 2/4 -> 22/4
3 3/4 -> 15/4
So now you can just do,
22/4 - 15/4,
which is just 7/4.
This in mixed number form is 1 3/4.
Answer:
<h2>

</h2>
Step-by-step explanation:
Given,
Perpendicular ( p ) = 3√2
Base ( b ) = 2√3
Hypotenuse ( h ) = ?
Now, let's find the length of the hypotenuse:
Using Pythagoras theorem:

plug the values

To raise a product to a power, raise each factor to that power

Multiply the numbers

Add the numbers

Take the square root of both sides of the equation

Hope this helps...
Best regards!!