Step-by-step explanation:
HCF of 60 and 84 = 6
So the required greatest number that divides 60 and 84 without leaving remainder is 6.
Answer:
(x + 2)² + (y - 1)² = 25
General Formulas and Concepts:
<u>Algebra I</u>
<u>Pre-Calc</u>
Circle Center Formula: (x - h)² + (y - k)² = r²
- <em>(h, k)</em> is center
- <em>r</em> is radius
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
<em>(h, k)</em> = (-2, 1)
<em>r</em> = 5
<u>Step 2: Find Equation</u>
- Substitute in variables [Circle Center Formula]: (x - -2)² + (y - 1)² = 5²
- Simplify: (x + 2)² + (y - 1)² = 25
Topic: Pre-Calculus
Unit: Conics
Book: Pre-Calculus (McGraw Hill)
<span>2√(x-5) = 2
</span><span>√(x-5) = 1
</span>x-5 = 1
x=6(I don't know what extraneous solution means though)
Answer:
1) To see whether it is a maximum or a minimum, in this case we can simply look at the graph. f(x) is a parabola, and we can see that the turning point is a minimum. By finding the value of x where the derivative is 0, then, we have discovered that the vertex of the parabola is at (3, −4).
2
