Answer:
Yes
Step-by-step explanation:
You would do 80 * 6/10, which equals 48. Therefore there would be 48 sixth graders at the morning assembly. Hope this helps. Please rate, leave a thanks, and mark a brainliest answer(Not necessarily mine). Thanks, it really helps! :D
Answer:
3+3+3x
i think idk just getting points goog luck
Step-by-step explanation:
Answer:
46
Step-by-step explanation:
With those problems if you are not given a picture is good we draw one.
Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then
m < XVY = m < YVW
2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms
2x-x = 15-7, combine like terms
x = 8
From the picture and the given we see that
m < XVW = m < XVY + m < YVW
m < XVW = 2x+7 + x+15 , combine like terms
m < XVW = 3x + 22, substitute x for 8
m < XVW = 3*8 + 22
m < XVW = 46
Check our work:
m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23
m < YVW = x+15 = 8 +15 = 23
m < XVW = m < XVY + m < YVW = 23+23 =46
Answer:
The rate of change is
ft^(2)/min
Step-by-step explanation:
The area of a circle is given by the following equation:

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

We have that:
.
We want to find 
So


Since the area is in square feet, the rate of change is in ft^(2)/min.
So the rate of change is
ft^(2)/min