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xz_007 [3.2K]
3 years ago
11

Solve for (m) 12.6+4m=9.6+8m m=?

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

m=3/4

m= 0.75

both of them are right

Step-by-step explanation:

Neporo4naja [7]3 years ago
5 0

Answer:

.75=m

Step-by-step explanation:

12.6-9.6=4m

3=4m

.75=m

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Answer:

1/4th of total cost = $12

so

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the game cost is $48

7 0
3 years ago
Read 2 more answers
Please help me!
Alexxandr [17]

A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.

We can use the Pythagorean formula to find the other leg of the right triangle.

a²+b²=c²

Where a and b are the legs of the triangle and c is the hypotenuse.

According to the given problem,

one leg: a= 5m and hypotenuse: c=13√5 m.

So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,

5²+b²=(13√5)²

25 + b² = 13²*(√5)²

25 + b² = 169* 5

25+ b² = 845

25 + b² - 25 = 845 - 25

b² = 820

b =√ 820

b = √(4*205)

b = √4 *√205

b = 2√205

b= 2* 14.32

b = 28.64

So, b= 28.6 (Rounded to one decimal place)

Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).

5 0
3 years ago
Jerrilyn wrote the following argument to prove that
likoan [24]

Answer:

absolutely no idea if this is right but i put the first one

Step-by-step explanation:

5 0
3 years ago
Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)
marshall27 [118]

Answer:

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

Step-by-step explanation:

Given

(4x^3y^5)(3x^5y)^2

Required

The equivalent expression

We have:

(4x^3y^5)(3x^5y)^2

Expand

(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2

Further expand

(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2

Apply laws of indices

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

8 0
3 years ago
Two negative integers are 5 units apart on the number line, and their product is 126. What is the sum of the two integers?
Tatiana [17]
If b>a, b-a=5 so b=5+a

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5a+a^2=126

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(a+14)(a-9)=0, since a<0 the numbers are

-14 and -9


7 0
3 years ago
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