Answer:
The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.
Step-by-step explanation:
Let <em>X</em> = number of students who have laptops.
The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.
A random sample of <em>n</em> = 30 students is selected.
The event of a student having a laptop is independent of the other students.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The mean and standard deviation of a binomial random variable <em>X</em> are:

Compute the mean of the random variable <em>X</em> as follows:

The mean of the random variable <em>X</em> is 1.11.
Compute the standard deviation of the random variable <em>X</em> as follows:

The standard deviation of the random variable <em>X</em> is 0.836.
<span>52 can be broken down to the following
2*26 =52
2*(2*13) <---13 x 2=26 x 2=52
2*2*13 or 2^2*13 <--BOTH mean the same thing :) </span><span>
</span>
The answer is 12 ÷ 3
Step-by-step explanation:
12 ÷ 3
4
Answer:
C
Step-by-step explanation:
Lucia's claim is correct since any rotation that is a multiple of 45° carries a square onto itself
Answer:
5 sessions each
Step-by-step explanation:
Let the personal training sessions be x.
<u>Then at Silver Gym Sarah would spend:</u>
<u>And at Fit Factor she would spend:</u>
<u>Since total costs are same, the amounts will be equal:</u>
- 35+30x = 85 + 20x
- 30x - 20x = 85 - 35
- 10 x = 50
- x= 50/10
- x= 5
So Sarah would buy 5 training sessions for each of the gyms.
And she would spend $185 at each.