Answer:
a.4845ways.
b. 14535ways.
c. 3990ways
d. 1140ways
Step-by-step explanation:
Given data:
No of flavors available to customers = 20.
Solution:
This is permutation and combinations problem,
(a) how many ways can the customers choose 4 different ice creams if they are all of different flavors.
20C4
= n!/(n-k)!)k!
= 20!/(20-4)!)4!
= 20!/(16)!)4!
= 4845ways.
b) are not necessarily of different flavors
Let’s say any two same flavors can be chosen.
20C4 * 3!/2!
= 4845 * 3
= 14535ways.
c) contain only 2 or 3 flavors.
= 20C3 * 3!/2!
= 1140 * 3
= 3420
20C2 * 3
= 190 * 3
= 570.
No of 2 or 3 different flavors
= 3420 + 570
= 3990ways.
d) contain 3 different flavors.
20C3
= n!/(n-k)!)k!
= 20!/(20-3)!)3!
= 1140ways.
If nine times n equals eleven than the value of n would be 11/9 and to get this all we have to do is divide both sides by 9.
Well, function is already written in "function notation" though not explicitly which I assume is "function notation".
Explicit notation for this function is:
Hope this helps.
Answer:
Step-by-step explanation:
5x + 4y = 20
You need to express y in terms of x.
isolate the y term
4y = -5x + 20
divide both sides by the coefficient of y
y = (-5/4)x + 5
f(x) = (-5/4)x + 5
