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Lisa [10]
2 years ago
15

Can someone help me please?

Mathematics
2 answers:
Fynjy0 [20]2 years ago
6 0

Answer:

3 mi because aa^{2}+b^{2}=c^{2}

which a= 5 mi and c= 8 mi so b is 8-5 which is 3, hope this helps :)

Eddi Din [679]2 years ago
5 0

Answer: can you turn the light up plz

Step-by-step explanation:

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Hope this helps! :D

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Determine the value of x.
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Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .
anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

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We need to begin with the definition of tangent:

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So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

cos(a-b) = cos(a) cos(b) + sin (a) sin(b)

If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

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My question has been deleted I made a mistake
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Retype your question that way we can help answer
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