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Natali5045456 [20]
3 years ago
13

PLEASE HELP ASAP !!!! THANKS

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

Its the first one

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Help please ASAP!!!! I NEED CORRECT ANSWERS ONLY FOR BRAINLIEST
ziro4ka [17]

we are given to find

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Write an equation for a line parallel to y=−4x+5 and passing through the point (4,-21)
Sindrei [870]

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Y=-4x-5

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3 years ago
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In a random sample of 80 teenagers, the average number of texts handled in one day is 50. The 96% confidence interval for the me
Naily [24]

Answer:

Standard deviation of the sample = 17.421

Step-by-step explanation:

We are given that in a random sample of 80 teenagers, the average number of texts handled in one day is 50.

Also, the 96% confidence interval for the mean number of texts handled by teens daily is given as 46 to 54.

So, sample mean, xbar = 50  and   Sample size, n = 80

Let sample standard deviation be s.

96% confidence interval for the mean number of texts,\mu is given by ;

    96% confidence interval for \mu = xbar \pm 2.0537*\frac{s}{\sqrt{n} }

                              [46 , 54]           = 50 \pm 2.0537*\frac{s}{\sqrt{80} }

Since lower bound of confidence interval = 46

So,  46 = 50 - 2.0537*\frac{s}{\sqrt{80} }

       50 - 46 = 2.0537*\frac{s}{\sqrt{80} }

            s = \frac{4*\sqrt{80} }{2.0537} = 17.421

Therefore, standard deviation of the sample is 17.421 .

3 0
4 years ago
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