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Paul [167]
3 years ago
13

(a) Find the common difference of an A.P. whose first term is 5 and the number of terms is 30 and sum 1455.

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0
Sum = n/2[2a + (n - 1)d] where a = first term, n = number of terms and d = common difference

(a) 30/2(2 x 5 + (30 - 1) x d) = 1455
10 + 29d = 1455 / 15
29d = 97 - 10
d = 87 / 29 = 3

(b) 7/2(2 x 9 + (7 - 1)d) = 0
18 + 6d = 0
6d = -18
d = -3
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Answer:

Gerrard

Step-by-step explanation:

Let the size of each poster be x

Eve's poster portion painted will be

=\frac{1}{6}\times x\\=\frac{x}6}

Gerrard's painted portion will be:

=\frac{1}{5}\times x\\=\frac{x}{5}

From the two inequalities, we find that \frac{x}{5} is greater than \frac{x}{6}  by x/30

\frac{x}{5}-\frac{x}{6}\\=\frac{x}{30}\\

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3 years ago
1) How many seconds are in three days?
Natasha_Volkova [10]

Answer:

259200 seconds

The conversion factor from days to seconds is 86400, which means that 1 day is equal to 86400 seconds:

1 d = 86400 s

To convert 3 days into seconds we have to multiply 3 by the conversion factor in order to get the time amount from days to seconds. We can also form a simple proportion to calculate the result:

1 d → 86400 s

3 d → T(s)

Solve the above proportion to obtain the time T in seconds:

T(s) = 3 d × 86400 s

T(s) = 259200 s

The final result is:

3 d → 259200 s

We conclude that 3 days is equivalent to 259200 seconds:

3 days = 259200 seconds

<em><u>Hope this helps :)</u></em>

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