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Paul [167]
3 years ago
13

(a) Find the common difference of an A.P. whose first term is 5 and the number of terms is 30 and sum 1455.

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0
Sum = n/2[2a + (n - 1)d] where a = first term, n = number of terms and d = common difference

(a) 30/2(2 x 5 + (30 - 1) x d) = 1455
10 + 29d = 1455 / 15
29d = 97 - 10
d = 87 / 29 = 3

(b) 7/2(2 x 9 + (7 - 1)d) = 0
18 + 6d = 0
6d = -18
d = -3
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The length of a rectangle is 4 cm more than the width. The are is 96 cm squared. Find the dimensions of the rectangle.
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3 0
3 years ago
Find the sum for:<br><br> (3x^2+4x−1)+(−2x^2−3x+2)=
Phantasy [73]

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7 0
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an engineer has a 54 inch wire that she has to cut into two pieces so that one piece is 8 inches shorter than the other find the
Brilliant_brown [7]

Hey there!!

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