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2 years ago

09.04 Continuity at a point Find the indicated limit, if it exists. (2 points)

Mathematics

1 answer:

LenKa [72]2 years ago

6 0

Answer:

Step-by-step explanation:

limit is defined when the limit from both side are defined and equal to f

$x-> -10^-$ , limit f(x)=-4-(-10)=6

f(-10)=6

$x-> -10^+$ , limit f(x)=(-10)+16=6

Then

$x->-10$ , limit f(x)=6

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6^2 times 3/2 dived by 71/54 plz actually help<br><br> anyone got pad let

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Answer:

41.0704225352 or 284x/9 + 0

Step-by-step explanation:

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3 years ago

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True or False:<br> There are an infinite number of answers for this equation:<br> 63 - X = 34

Shtirlitz [24]

Answer: No, the answer is 29, this is false.

Step-by-step explanation: 63-x=34

subtract 63 from both sides

34-63= -29

-x=-29

divide both sides by the negative and you get 29

plug in 29 for x, 63-29=34

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3 years ago

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(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13

jolli1 [7]

Answer:

$y(x)=3e^{5x}-2xe^{5x}$

Step-by-step explanation:

The given differential equation is $y''-10y'+25y=0$

The characteristics equation is given by

$r^2-10r+25=0$

Finding the values of r

$r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5$

We got a repeated roots. Hence, the solution of the differential equation is given by

$y(x)=c_1e^{5x}+c_2xe^{5x}...(i)$

On differentiating, we get

$y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)$

Apply the initial condition y (0)= 3 in equation (i)

$3=c_1e^{0}+0\\\\c_1=3$

Now, apply the initial condition y' (0)= 13 in equation (ii)

$13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2$

Therefore, the solution of the differential equation is

$y(x)=3e^{5x}-2xe^{5x}$

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3 years ago

Which of the following ordered pairs is a solution to the equation? (-4,-1) (-2,0) (0,3) (9,1)

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The answer is (0,3) the line hits at positive 3

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2 years ago

Mr. Martin’s math test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Let x be

klio [65]

(x + y = 29)
(y = 29 - x)
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3 years ago

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