9(x + 1)^4 - 19(x + 1)^2 + 2 = 0
After expanding and re-factoring, we have:
(3x + 2)(3x + 4)(x^2 + 2x - 1) = 0
solutions are x = -2/3, x = -4/3, x = -1 - sqrt(2), x = sqrt(2) - 1
You have to multiply 3 by 10 and 8 by 3, then subtract them
30/80 - 24/80 = 6/80
then simplify
6/2 and 80/2
3/40
Answer:
Part A). 25 feet
Part B). 16.25 feet
Step-by-step explanation:
Part A). By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
AC² = (24)² + 7²
AC² = 576 + 49
AC = √625
= 25 feet
Part B). By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
(25)² = (19)² + x²
625 = 361 + x²
x² = 625 - 361
x = √264
x = 16.25 feet
Answer:
D. p + q = 7
Step-by-step explanation:
The slope of AB is ...
mAB = (y2 -y1)/(x2 -x1) = (1 -4)/(6 -p) = -3/(6 -p)
The slope of BC is ...
mBC = (q -1)/(9 -6) = (q -1)/3
We want the product of these slopes to be -1:
mAB·mBC = -1 = (-3/(6 -p))·((q -1)/3)
-(q-1)/(6 -p) = -1 . . . . cancel factors of 3
q -1 = 6 -p . . . . . multiply by -(6 -p)
q + p = 7 . . . . . matches choice D