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Greeley [361]
3 years ago
12

Mr. Martin’s math test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Let x be

the number of questions worth 5 points and let y be the number of questions worth 2 points. x + y = 29, 5x + 2y = 100 How many problems of each point value are on the test?
Mathematics
2 answers:
klio [65]3 years ago
6 0
(x + y = 29)
(y = 29 - x)
(5x + 2(29 - x) = 100)
(5x + 58 - 2x = 100)
(3x = 42)
(x = 14)
(y = 15)
(14 5-point questions and 15 2-point questions)
zimovet [89]3 years ago
5 0

Answer:

b

Step-by-step explanation:

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Solve the equation 9 (x+1)^4-19 (x+1)^2+2=0
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9(x + 1)^4 - 19(x + 1)^2 + 2 = 0
After expanding and re-factoring, we have:
(3x + 2)(3x + 4)(x^2 + 2x - 1) = 0
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4 years ago
I need help with number 4 please help
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You have to multiply 3 by 10 and 8 by 3, then subtract them

30/80 - 24/80 = 6/80

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3/40

6 0
4 years ago
Read 2 more answers
Part A )a painter leans a ladder up against a building. The base of the ladder is placed 7 feet from the building to reach a hei
Lana71 [14]

Answer:

Part A). 25 feet

Part B). 16.25 feet

Step-by-step explanation:

Part A). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

            AC² = (24)² + 7²

            AC² = 576 + 49

            AC = √625

                  = 25 feet

Part B). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

           (25)² = (19)² + x²

           625 = 361 + x²

           x² = 625 - 361

           x = √264

           x = 16.25 feet

4 0
3 years ago
When somebody tells there friend there da best does that mean they think that they’re better then anyone else???
Otrada [13]

Answer:

Yep

Step-by-step explanation:

7 0
3 years ago
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The coordinates of A, B, and C in the diagram are A (p, 4), B (6, 1 ), and C (9, q). Which equation correctly relates p and q? ↔
aivan3 [116]

Answer:

  D.  p + q = 7

Step-by-step explanation:

The slope of AB is ...

  mAB = (y2 -y1)/(x2 -x1) = (1 -4)/(6 -p) = -3/(6 -p)

The slope of BC is ...

  mBC = (q -1)/(9 -6) = (q -1)/3

We want the product of these slopes to be -1:

  mAB·mBC = -1 = (-3/(6 -p))·((q -1)/3)

  -(q-1)/(6 -p) = -1 . . . . cancel factors of 3

  q -1 = 6 -p . . . . . multiply by -(6 -p)

  q + p = 7 . . . . . matches choice D

8 0
3 years ago
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