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2 years ago

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a school bus has 22 rows of seats, and 4 students can be seated in each row/ students riding in the bus have filled 19 rows of s

eats and 1/2 of the remaining seats. how many seats on the bus are empty?

1 answer:

Andreas93 [3]2 years ago

7 0

4 sears cuz 22-1& is 2 and 1/2 of 2 is 1 and 1 row seats 4 students

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At last, we stopped running. Relief washed over us. Whatever had been chasing us was long gone. We were home and finally safe be

Dmitry_Shevchenko [17]

Answer:

The author is stating his or her feelings.

Step-by-step explanation:

It says "Relief washed over us. Whatever had been chasing us was long gone. We were home and finally safe behind a locked door." She's /he's telling the emotions.

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2 years ago

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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

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Find the inverse of the following function. f(x) =^3squareroot x + 12<br><br> I NEED AN ANSWER NOWW

makkiz [27]

Answer:

(x - 12)²/9

Step-by-step explanation:

y = 3sqr(x) + 12

Make x the subject:

y - 12 = 3sqrt(x)

(y - 12)/3 = sqrt(x)

Square both sides

(y - 12)²/9 = x

Interswitch variables

inverse function is:

(x - 12)²/9

If f(x) = (x + 12)^⅓

Then,

y = (x + 12)⅓

y³ = x + 12

y³ - 12 = x

f inverse:

x³ - 12

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3 years ago

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2(4x-5)=2(4+3x) What the Equation PLZ HELPPP

Bezzdna [24]

Answer:

x = 9

Step-by-step explanation:

ur welcome

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3 years ago

8х + 5у = -7<br> — 7х + бу = — 4

Levart [38]

Answer: x = -0.2651 and y = -0.9759

Step-by-step explanation:

Solution by substitution method

8x+5y= -7

-7x+6y= -4 = 7x-6y=4

Suppose,

8x+5y=-7→(1)

7x-6y=4→(2)

Taking equation (1), we have

8x+5y= -7

⇒8x= -5y -7

⇒x= -5y-7 / 8 →(3)

Putting x= -5y-7 / 8

in equation (2), we get 7x-6y=4

7(-5y-7/8)-6y=4

⇒-35y-49-48y=32

⇒-83y-49=32

⇒-83y=32+49

⇒-83y=81

⇒y= 81 / -83

⇒y= -0.9759→(4)

Now, Putting y= -0.9759 in equation (3), we get

x= -5y-7

x= -5(-0.9759)-7/8

⇒x= 4.8795-7/8

⇒x= -2.1205/8

⇒x= -0.2651

∴x= -0.2651 and y = -0.9759

7 0

2 years ago