1. b - plants make their own food (glucose)
2. 1 - fish and upwards have a jaw (there are fish that do not have jaws, but this is likely where the divergence happens - before 1 is likely jawless fish.
3. b - cellular respiration
4. They belong to the same kingdom (Animalia) but different phyla (dogs are in the phylum Chordata - insects are not)

7 0

3 years ago

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The (blank) is the the height of the wave and measures the amount of (blank) it carries.

Vsevolod [243]

Amplitude

Energy

Explanation:

The amplitude is the height of the wave and measures the amount of energy it carries.

Amplitude of a wave is the maximum amount of displacement of wave from rest.

The energy of the a wave is the amount of disturbance a wave transmits.

The amplitude of a wave is the wave height.
It measures the vertical height through which a wave passes through.
Waves that have a high vertical displacement i.e high amplitude carries a lot of energy.

E = kA²

where E is wave energy , k is the wave number and A is the amplitude of the wave.

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7 0

3 years ago

A couple without an ancestral history of Tay-Sachs disease (a rare autosomal recessive) have two normal children and an infant a

Bas_tet [7]

Answer:

The probability is 25%.

Explanation:

Let the dominant allele for the disease be 'T' and recessive allele be 't'.

The couple with normal phenotype produces an infant with the Tay Sach's disease.
As the disease is autosomal recessive in nature, it will get expressed in a homozygous recessive condition, that is, when the genotype is : tt.
As the normal parents are producing a diseased offspring, the both parents must be heterozygous dominant (Tt) for the disease allele.
The brother of the husband and the sister of the wife, both having a normal phenotype, can have the following genotypes, TT or Tt.
If either of the individual (brother or sister) has TT genotype and the other has other has either TT or Tt genotype, there is zero probability that they will produce an offspring with the disease.

T T and T T

T TT TT T TT TT

(N) (N) (N) (N)

T TT TT t Tt Tt

(N) (N) (N) (N)

If both the individuals have a Tt genotype, the probability to produce diseased offspring is one-fourth or 25%.

T t

T TT Tt

(N) (N)

t Tt tt

(N) (D)

(N) stands for normal and (D) stands for diseased phenotype.

7 0

4 years ago

13. Given the original DNA strand, which of the following would be the new, complementary strand

Alex Ar [27]

Answer:

TGAATGCGGCTA

Explanation:

The complementary DNA codes for A is T and for G its C

4 0

3 years ago

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