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viva [34]
3 years ago
7

Suppose a jar contains 8 red marbles and 25 blue marbles. If you reach in the jar and pull out 2 marbles at random, find the pro

bability that both are red.
Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer: \dfrac{7}{132}

Step-by-step explanation:

Total marbles in the jar =  8+25 = 33

Using combinations, the number of ways of choosing two marbles out of 33=  \dfrac{33!}{2!(33-2)!}\\\\=\dfrac{33!}{2\times31!}\\\\=\dfrac{33\times32}{2}=528  (total outcomes)

Similarly, the number of ways of choosing two red marbles =

\dfrac{8!}{2!6!}\\\\=\dfrac{8\times7}{2}=28(favorable outcomes)

Required probability = \dfrac{\text{favorable outcomes}}{\text{total outcomes}}

=\dfrac{28}{528}\\\\=\dfrac{7}{132}

hence, required probability = \dfrac{7}{132}

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