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mart [117]
2 years ago
6

1. What is the remainder when x³+4x2-2x+1 is divided by x+2 1. What is the remainder when x³ + 4x2-2x + 1 is divided by x + 2​

Mathematics
1 answer:
ELEN [110]2 years ago
3 0

Answer:

Remainder is 13

Step-by-step explanation:

You can apply the remainder theorem here. You just equate the divisor to 0, then substitute the x-value in the expression.

x^3 + 4x^2 - 2x + 1       \\       then, x+2=0\\x=-2

substitute:

-2^3 + 4(-2)^2-2(-2) + 1 =13

Therefore, the remainder is 13

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Solve the equation. Round to the nearest hundredth. Show work.
muminat

Answer:

Final answer is approx x=0.16.

Step-by-step explanation:

Given equation is 2.8\times 13^{4x} +4.8 = 19.3

Now we need to solve equation 2.8\times 13^{4x} +4.8 = 19.3 and round to the nearest hundredth.

2.8\times 13^{4x} +4.8 = 19.3

2.8\times 13^{4x} = 19.3-4.8

2.8\times 13^{4x} = 14.5

13^{4x} = \frac{14.5}{2.8}

13^{4x} = 5.17857142857

\log(13^{4x}) = \log(5.17857142857)

4x \log(13) = \log(5.17857142857)

4x = \frac{\log(5.17857142857)}{\log\left(13\right)}

4x = 0.641154659628

x = \frac{0.641154659628}{4}

x = 0.160288664907

Round to the nearest hundredth.

Hence final answer is approx x=0.16.

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