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mario62 [17]
2 years ago
8

How do you find the equations of the vertical and horizontal asymptotes for a graph when you only have the graph and no function

?
Mathematics
1 answer:
-BARSIC- [3]2 years ago
8 0

Answer:

See below for answer and explanations (as well as an attached graph)

Step-by-step explanation:

Pay attention to the behavior of the asymptotes. If the asymptotes are approaching a certain x-value or y-value, then that value is undefined for the function.

Take for example y=\frac{1}{x}:

  • As x approaches ∞ and -∞, then y approaches 0, which is our horizontal asymptote
  • As y approaches ∞ and -∞, then x approaches 0, which is our vertical asymptote

See the graph for a visual.

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bulgar [2K]

Answer:

\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}

Step-by-step explanation:

Given

\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}

Required

Fill in the gaps

Going by the given parameters, we have that

\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}

x^2 - 9x + 8, when factorized is (x-1)(x-8)

Hence; the expression becomes

\frac{4x+2}{(x-1)(x-8)} = \frac{A}{(x-8)(x-1)} + \frac{B}{(x-1)(x-8)}

Combine Fractions

\frac{4x+2}{(x-1)(x-8)} = \frac{A + B}{(x-8)(x-1)}

Simplify the denominators

4x + 2 = A + B

By direct comparison

A = 4x

B = 2

Hence, the complete expression is

\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}

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The ratio of the ages (in years) of two teachers is 8 : 9. The sum of their ages is 51. What is the age of each teacher?
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Help it will really hep with summer school.
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<h2> Hey, Option C is correct.....</h2>

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