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sleet_krkn [62]

2 years ago

14

The mass of a patient decreased by 20 percent every month. If his mass before the decrease was 90kg, how many kilograms had he l

ost after 3 months ?

1 answer:

Vadim26 [7]2 years ago

7 0

I believe it’s 36kg

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Please help me<br> This is analytic geometry

Vlada [557]

Answer:

The coordinates of point B are (-3,-3).

Step-by-step explanation:

Let $A(x,y) = (6,-6)$ , $C(x,y) = (-6,-2)$ and $\overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}$ , then we have the following formula by vectorial definition of a line segment:

$\overrightarrow{AB} = \frac{3}{4}\cdot \overrightarrow{AC}$

$B(x,y) -A(x,y) = \frac{3}{4}\cdot [C(x,y)-A(x,y)]$

$B(x,y) = \frac{3}{4}\cdot C(x,y) +\frac{1}{4}\cdot A(x,y)$

$B(x,y) = \frac{3}{4}\cdot (-6,-2)+\frac{1}{4}\cdot (6,-6)$

$B(x,y) = (-3, -3)$

5 0

2 years ago

Which postulate can be used to prove that the triangles are congruent?

Varvara68 [4.7K]

Haven't been taught this; but from what I searched up; I think the postulate for proving these shapes' congruence is Hypotenuse/Leg. I have no exact idea however. Correct me if I'm wrong :/

5 0

2 years ago

Read 2 more answers

(x-3) (x2+2x+1)<br> Foil method

AveGali [126]

Step-by-step explanation:

(x-3)(x^2+2x+1)

=x^3-3x^2+2x^2-6x+x-3

=x^3+2x^2-3x^2-6x+x-3

=x^3-x^2-5x-3

___________

8 0

3 years ago

Allisa [31]

<span>6x + 10 = 4x -8
6x-4x = -8 - 10
2x = -18
x = -9

answer
</span><span>exactly one solution</span>

6 0

2 years ago

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An arc measures 50°in a circle with a radius of 8 cm. What is the area of the sector to the nearest tenth of a square centimeter

marysya [2.9K]

Answer:

$27.9cm^2$

Step-by-step explanation:

The <u>total area</u> of the circle is given by:

$a=\pi r^2$

where $\pi$ is a constant $\pi=3.1416$

and $r$ is the radius: $r=8cm$

Thus the total area of this circle is:

$a=(3.1416)(8cm)^2\\a=(3.1416)(64cm^2)\\a=201.06cm^2$

We want only the area of the arc that measures 50°. For this we must remember that the arc of the total circle is 360°.

Thus, we want 50° out of the 360° degrees in the circle. For this, we divide the total area by 360 and then we multiply by 50:

$\frac{201.06cm^2}{360}(50)=0.5585cm^2(50)=27.9cm^2$

the area of the sector to the nearest tenth is $27.9cm^2$

3 0

3 years ago