The genotype would be X'Y for the father (he would be colorblind)
The genotype would be X'X for the mother (she would be a carrier)
The offspring would be X'X' _ X'X_ X'Y_ XY
The ratio would be 1:1 normal to colorblind
Hope this was helpful(;
Speed = distance ÷ time.
1864/42=44.38
Answer:
its option A. bright tail feathers of peacocks during breeding season
Explanation:
Answer:
2.Less than 73% of the populations would have only one allele present.
Explanation:
The two alleles chosen do not affect the fitness of flies in the lab environment, so Kerr and Wright could be confident that if changes in the frequency of normal and forked phenotypes occurred, they would not be due to natural selection.
Using a larger breeding population would not be expected to alter the outcome of the experiment.