X=2
y=0
Answer in photo below. Good luck
Answer:
20
Step-by-step explanation:
4004 + 50.50t = 300.75t
4004 = 300.75t - 50.50t
4004 = 250.25t
4004 / 250.25 = t
16 = t <=== they charge the same at 16 tons
300.75(16) = 4812 <== they cost the same
Let the smaller odd integer be x and the larger be x + 2.
![x + x + 2 \leqslant 46 \\ 2x + 2 \leqslant 46 \\ 2x \leqslant 44 \\ x \leqslant 22 \\ x = 21](https://tex.z-dn.net/?f=x%20%2B%20x%20%2B%202%20%5Cleqslant%2046%20%5C%5C%202x%20%2B%202%20%5Cleqslant%2046%20%5C%5C%202x%20%5Cleqslant%2044%20%5C%5C%20x%20%5Cleqslant%2022%20%5C%5C%20x%20%3D%2021)
21, 23
Answer:
The motorist's average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.
Step-by-step explanation:
Let the motorist's average rate in the afternoon = <em>x</em> mph.
It is given that his average rate in the morning was twice his average rate in the afternoon.
Therefore, his average rate in the morning = 2<em>x</em> mph.
Let <em>t</em> be the time taken for the morning trip.
It is given that he spent 5 hours for driving.
So, the time taken by him for the afternoon trip = 5 - <em>t</em>.
Now, using the formumla,
,
the verbal model for the morning trip is:
![2x=\frac{150}{t}](https://tex.z-dn.net/?f=2x%3D%5Cfrac%7B150%7D%7Bt%7D)
<em>xt</em> = 75
The verbal model for the afternoon trip is:
![x=\frac{50}{5-t}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B50%7D%7B5-t%7D)
5<em>x</em> - <em>xt</em> = 50
Substituting <em>xt</em> = 75, we get,
5<em>x</em> - 75 = 50
5<em>x</em> = 125
<em>x</em> = 25
2<em>x</em> = 50
Hence, his average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.