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garik1379 [7]
3 years ago
5

Mrs. DeMarco wants to estimate the height of her garage

Mathematics
1 answer:
valkas [14]3 years ago
6 0

Answer:

length of baseball bat.

Step-by-step explanation:

she can measure the bat and times by how many times she could fit the bat there u know

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nikklg [1K]

Answer:

E      

Step-by-step explanation:

19)        Amount of oil in   =    amount of oil in final product

       .025(x) + .09(40-x)    =    .055(40)      (x = 2.5% amt   40 - x = 9% amt)

  x = 21.54 L  of   2.5 %     then 9% = 18.46 L

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How can you find a trigonometric function of an acute angle 0 ?​
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The characteristics of similar triangles, originally formulated by Euclid, are the building blocks of trigonometry. Euclid's theorems state if two angles of one triangle have the same measure as two angles of another triangle, then the two triangles are similar. Also, in similar triangles, angle measure and ratios of corresponding sides are preserved. Because all right triangles contain a 90° angle, all right triangles that contain another angle of equal measure must be similar. Therefore, the ratio of the corresponding sides of these triangles must be equal in value. These relationships lead to the trigonometric ratios. Lowercase Greek letters are usually used to name angle measures. It doesn't matter which letter is used, but two that are used quite often are alpha (α) and theta (θ).
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Find the absolute value.<br> What is the absolute value of four
iren [92.7K]

Answer:

whats the graph???

Step-by-step explanation:

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Which equation can be used to find the length of AC?
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Read 2 more answers
It’s a precalculus holiday equation. Need to simplify to find the “secret message” can anyone help???
tensa zangetsu [6.8K]

Take the expression in chunks:

>>

((X+A)(X-A)M+A^2M)E=((X^2-A^2)M+A^2M)E=X^2ME

>>

\dfrac{\frac{R+X}X+\frac X{R-X}}{\frac X{R-X}}=\dfrac{\frac{R+X}X}{\frac X{R-X}}+1

\dfrac{\frac{(R+X)(R-X)}{X(R-X)}}{\frac{X^2}{X(R-X)}}=\dfrac{(R+X)(R-X)}{X^2}=\dfrac{R^2-X^2}{X^2}=\dfrac{R^2}{X^2}-1

\implies\dfrac{\frac{R+X}X+\frac X{R-X}}{\frac X{R-X}}=\dfrac{R^2}{X^2}

>>

Note that (a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab. So

\displaystyle\frac{4AS}3\sum_{\rm cyc}\frac1{X((E+Y)^2-(E-Y)^2)}=\frac{4AS}3\sum_{\rm cyc}\frac1{4XEY}=\frac{AS}3\sum_{\rm cyc}\frac1{XEY}

where the cyclic sum notation means

\displaystyle\sum_{\rm cyc}f(x,y,z)=f(x,y,z)+f(z,x,y)+f (y,z,x)

In other words, we take the sum over all possible cycles of the sequence of arguments to the summand. The second square-bracketed chunk reduces to

\displaystyle\frac{AS}3\sum_{\rm cyc}\frac1{XEY}=\frac{AS}3\left(\dfrac1{XEY}+\dfrac1{EYX}+\dfrac1{YXE}\right)=\dfrac{AS}3\dfrac3{XEY}=\dfrac{AS}{XEY}

So to recap, we've reduced the starting expression to

X^2ME\left(\dfrac{R^2}{X^2}-\dfrac{AS}{XEY}\right)Y

>>

\dfrac{R^2}{X^2}-\dfrac{AS}{XEY}=\dfrac{R^2EY-ASX}{X^2EY}

Finally, we have

X^2ME\dfrac{R^2EY-ASX}{X^2EY}Y=M(R^2EY-ASX)

Then distributing M and rewriting to decode the message, we have

MERRY-XMAS

6 0
3 years ago
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