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DanielleElmas [232]

2 years ago

11

What is the greatest common factor of 100 and 20

2 answers:

Nady [450]2 years ago

6 0

20
20 = 1 x 20
100 = 5 x 20

Ronch [10]2 years ago

6 0

20 goes into its self once and 100 5 times so 20 is the greatest common factor

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Please answer the 2 questions if you can? (This is my math from 8th grade)

LUCKY_DIMON [66]

Answer:

Hi myself Shrushtee.

Step-by-step explanation:

8) a) x = 8.

10) c) x = 3

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2 years ago

Last month Marybeth was charged $112for a 945kWh of electricity. How much did the company charger her per kWh, to the nearest ce

Usimov [2.4K]

She was charged 12 cents per kWh

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2 years ago

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Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ

tensa zangetsu [6.8K]

Answer: RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{18+x}{tan 75^{\circ}}$

Now, In triangle MRQ,

tan 60°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{x}{tan 60^{\circ}}$

On equating both values of RQ,

$\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=2.15470053838$

⇒ $18=2.15470053838x-x$

⇒ $x=15.5884572681$ ≈15.60

Thus RQ=8.99999999999≈8.99

6 0

2 years ago

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=26°, and QO = 4.9 feet. Find the length of PQ to the nearest tenth of a foot.

Step2247 [10]

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

$m\angle O+m\angle P+m\angle Q=180^\circ$ [Angle sum property]

$26^\circ+m\angle P+90^\circ=180^\circ$

$m\angle P+116^\circ=180^\circ$

$m\angle P=180^\circ -116^\circ$

$m\angle P=64^\circ$

According to Law of Sines, we get

$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$

Using the Law of Sines, we get

$\dfrac{p}{\sin P}=\dfrac{o}{\sin O}$

$\dfrac{QO}{\sin P}=\dfrac{PQ}{\sin O}$

Substituting the given values, we get

$\dfrac{4.9}{\sin (64^\circ)}=\dfrac{PQ}{\sin (26^\circ)}$

$\dfrac{4.9}{0.89879}=\dfrac{PQ}{0.43837}$

$\dfrac{4.9}{0.89879}\times 0.43837=PQ$

$2.38989=PQ$

Approximate the value to the nearest tenth of a foot.

$PQ\approx 2.4$

Therefore, the length of PQ is 2.4 ft.

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2 years ago

CAN ANYONE HELP ME ANSWER THIS

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I think is dependent

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2 years ago

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