Question 1:
If you know that 3 squares equals 7 circles and the squares are being counted by 3, then continue to count the circle by 3 until you get 25 circles.
Example:
3 Squares : 7 circles
4 squares : 10 circles
5 squares : 13 circles
6 squares : 16 circles
7 squares : 19 circles
8 squares : 22 circles
9 squares : 25 circles Add 9 squares to 3 = 12
You will have 12 squares when continues to count all the way to 25 circles.
Question 2:
Just multiply 14 by 28 and you will get your answer. Which is 3. The missing digit's 3. You can then check by doing 392 ÷ 14 to see if you get 28.
Answer:
(a) f(0) = 1
(b) f(3) = 5 (I'm not sure about this one, it's either this or undefined)
(c) f(-2) = 3
(d) 
(e) 
(f) 
(g) 
DNE, because the limit of x--> 1 from the left is 2, and the limit from the right is 1. Because they don't approach the same value from both sides, the limit doesn't exist.
Answer:
27
Step-by-step explanation:
The third side must be shorter than the other 2 sides added together.
13 + 15 = 28, so at most it can be 27 , since it needs a whole number
Bug zapper #1 zapped 103 bugs
103 + 22 = 125
125 + 45 = 170
103 + 125 + 170 = 398
Answer:
Step-by-step explanation:
y = 2x-5
x= -2
y = 2(-2) -5 = -4 -5 = -9
x= 0
y = 2·0 -5 = -5
x= 1
y = 2·1 -5 = 2-5 = -3
x= 4
y = 2·4 -5 = 8 -5 = 3
x | -2 -1 0 1 2 3 4
-------------------------------------------------------
y | -9 -7 -5 -3 -1 1 3
