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3 years ago

Solve each one step equation, use your answers to navigate through the maze. Show your work on a separate page

Mathematics

1 answer:

mixas84 [53]3 years ago

5 0

Answer:

Step-by-step explanation:

I think thats how its done, sorry for messy handwriting

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if a store uses a selling price based markup of 40% and an item cost the store $300 what selling price would the store set for t

kirza4 [7]

Answer:

The selling price would be $420.

Step-by-step explanation:

In order to find the mark up, we need to multiply the amount it originally costs by the percentage it is being marked up.

$300 * 40% = $120

Now that we have the mark up amount, we add it to the original cost to get the sale price.

$300 + $120 = $420

6 0

3 years ago

Write the following inequality in slope-intercept form. –12x – 2y ≥ –42 y ≥ –6x – 21 y ≤ –6x – 21 y ≤ –6x + 21 y ≥ –6x + 21

xxMikexx [17]

Answer:

y ≤ –6x + 21

Step-by-step explanation:

5 0

3 years ago

Find the missing number in this sequence<br> 1,0,1,1,0,1,_.1.0.1.1.1.10

Softa [21]

Answer:

Step-by-step explanation:

look at the first numbers

8 0

3 years ago

Read 2 more answers

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays. Assuming the

AysviL [449]

Answer:

1.83% probability there are no car accidents on that stretch on Monday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays.

This means that $\mu = 4$

What is the probability there are no car accidents on that stretch on Monday?

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4}*(4)^{0}}{(0)!} = 0.0183$

1.83% probability there are no car accidents on that stretch on Monday

5 0

3 years ago

4x^2-5x-15=0 how to find the vertex and y intercept

mezya [45]

$ax^2+bx+c=0\\\\the\ vertex:\left(\frac{-b}{2a};\frac{-(b^2-4ac)}{4a}\right)\\\\y-intrcept=c\\=======================================\\\\4x^2-5x-15=0\\\\a=4;\ b=-5;\ c=-15\\\\\frac{-b}{2a}=\frac{-(-5)}{2\cdot4}=\frac{5}{8};\ \frac{-(b^2-4ac)}{4a}=\frac{-[(-5)^2-4\cdot4\cdot(-15)]}{4\cdot4}=-\frac{265}{16}\\\\\boxed{the\ vertex:\left(\frac{5}{8};-\frac{265}{16}\right)}\\\\\boxed{y-intercept:-15}$

5 0

3 years ago