Need help gotta turn in at midnight

Mathematics

1 answer:

blondinia [14]3 years ago

6 0

Answer:

Step-by-step explanation:

If its isoceles, then LM is equal to LN. This means 3x-2 = 2x+1. 3x minus 2x is x. 2 plus 1 is 3. So x = 3. So it needs to be c or d. since LM and LN are the same answers, go to MN and find the answer. If you siubstitute 3 for x in 5x-2, then you get 13.

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line m contains the points -3,4 and 1,0. write the equation of a line that would be perpendicular to this one and pass through t

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The equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6) in point slope form is y = x + 8

<h3>Solution:</h3>

Given that line m contains points (-3, 4) and (1, 0)

We are asked to find the equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6)

Let us first find slope of the line "m"

Given two points are (-3, 4) and (1, 0)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$\left(x_{1}, y_{1}\right)=(-3,4) \text { and }\left(x_{2}, y_{2}\right)=(1,0)$

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Thus slope of line m is -1

We know that product of slope of given line and perpendicular line are always -1

So, we get

$\begin{array}{l}{\text { slope of line } m \times \text { slope of perpendicular line }=-1} \\\\ {-1 \times \text { slope of perpendicular line }=-1} \\\\ {\text { slope of perpendicular line }=1}\end{array}$