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klasskru [66]
3 years ago
8

1.Were your two estimates the same? Did the mean length of all the straws in the bag change in between selecting the two samples

? Explain your reasoning.
2.The actual mean length of all of the straws in the bag is about 2.37 inches. How do your estimates compare to this mean length?

3.If you repeated the same process again but you selected a larger sample (such as 10 or 20 straws, instead of just 5), would your estimate be more accurate? Explain your reasoning.





Remember that sample 1 mean= 4


Sample 2 mean = 3.8
Mathematics
2 answers:
RUDIKE [14]3 years ago
6 0
14.8, 16/3 and 16.2637
wariber [46]3 years ago
5 0
1. 14.8
2. 16/3
3. 16.2637
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20,18,13,17,18 find the mean,median and mode​
Degger [83]
<h3>Answer:</h3>

Mean: 17.2

Median: 18

Mode: 18

<h3>Solution:</h3>

Mean: The sum of all observation divided by several observation

  • 20+18+13+17+18=86
  • 86÷5=
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Median:it is the middlemost observation of data arraged in increasing or decreasing order of values

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Mode:it is the value that occurs frequently in a set of data

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Hope it helps

6 0
2 years ago
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An urn contains 8 pink and 5 red balls. Six balls arerandomly drawn from the urn in succession, with replacement.That is, after
slega [8]

0.088

Step-by-step explanation:

The total number of balls in the urn is;

8 +  5 = 12

Because the pink balls are 8, then the probability of picking a pink ball from the urn is;

8/12

To get the probability that all 6 balls drawn from the urn are pink, we will use the AND probability rule of the mutually exclusive events which means we’ll multiply the probabilities of each of the six pink balls;

8/12 * 8/12 * 8/12 * 8/12 * 8/12 * 8/12

= 0.088

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6 0
3 years ago
The hypotenuse of a right-angled triangle is 61 cm. If one of the remaining two sides is
igomit [66]

Answer:

60cm

Step-by-step explanation:

the length of other side = sqrt (square root) hypotenuse^2 - the length of thrid side^3 = sqrt 61^2 - 11^2 = sqrt 60^2 =  60

8 0
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Your answer is 21...

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Suppose instead of comparing independent measurements taken from two groups, you used a matched-pairs experiment and one treatme
lina2011 [118]

You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence

Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.

Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)

After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences

The confidence interval is in the form (L, U)

L = lower bound

L = dbar - t*sd/sqrt(n)

U = upper bound

U = dbar + t*sd/sqrt(n)

3 0
3 years ago
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