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3 years ago

Can someone please solve 3x^2+4x-7<13

1 answer:

6 0

Answer:

$-\frac{10}{3}$

Step-by-step explanation:

Rewrite in standard form: $3x^2+4x-20$

Factor: $\left(x-2\right)\left(3x+10\right)$

Solve individually for x:

$x-2$

$3x+10$

Combine:

$-\frac{10}{3}$

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