For the answer to the question above asking <span>What additional information would you need to prove that ΔABC ≅ ΔDEF by SSS?
The answer to your question is </span><span>AB = DE & BC = EF, so the only sides missing are AC = DF, </span>
<span>so Side AC is congruent to side DF is the answer.
I hope my answer helped you. Have a nice day!
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(r, theta)= (8, 3/2 pi)
r=(x^2 +y^2)^(1/2)
theta= 3/2 pi
x= r(costheta)
y=r(sintheta)
x=8(cos(3/2 pi))
y=8(sin(3/2 pi))
x=8(0)
y=8(-1)
x=0
y=-8
r=((-8)^2+(0)^2)^(1/2)
r=(64+0)^(1/2)
r=8
rectangular coordinates= (0,-8)
if RD is 12cm so AR is 12cm too... since the R is placed in the middle and we can analyze too that the AD is 24cm since RD is 12cm and AR is 12cm so...
12+12=24
AR= 12cm
<em>Hope it helps...</em>