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Ivan
3 years ago
14

Describe julius caesar as a child

Mathematics
1 answer:
lianna [129]3 years ago
8 0

Answer:

You dare challenge me...

Step-by-step explanation:

Gaius Julius Caesar was a Roman general and statesman who played a critical role in the events that led to the demise of the Roman Republic and the rise of the Roman Empire. In 60 BC, Caesar, Crassus and Pompey formed the First Triumvirate, a political alliance that dominated Roman politics for several years.

You might be interested in
Find the zeros of the polynomial x^2 + 8x + 16
Scorpion4ik [409]

hey mate,

x^2 + 8x + 16 = 0

<=>

(x+4)^2 = 0

As we know that (a+b)^2 = a^2+b^2+2ab

then

(x+4)^2 = 0

<=> (x+4) = 0

<=> x = -4

so there is one solution x = -4

thanks

4 0
3 years ago
Plz help asap and plz show me how to do this..thxs I really need help with this
Fed [463]
 G is the answer because if you set x as the value of B, then x+(x+10)+(x+30)=180 so x=46.67. then you add 10 to that because the value of A is 10 more than B
3 0
3 years ago
What is the coefficient in the expression 15y + 5
dalvyx [7]

Answer:

15

Step-by-step explanation:

If helpful, please give 5 star, thanks, and brainliest!

8 0
2 years ago
Read 2 more answers
- 1/6 [ 3 - 15 (1/2)2]
bonufazy [111]

Answer:

Your answer is -2

Step-by-step explanation:

1/6 [ 3 - 15 1/2 x 2 ] = -2/1 = -2

Hope this helps : )

8 0
1 year ago
40, 10, 5/2 5/8... (fractions) is it arithmetic or geometric and what are the next two terms PLZ HELP DUE IN 10 MINS
patriot [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

40,\:10,\:\frac{5}{2},\:\frac{5}{8}

A geometric sequence has a constant ratio 'r' and is defined by

\:a_n=a_0\cdot r^{n-1}

Computing the ratios of all the adjacent terms

\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}

The ratio of all the adjacent terms is the same and equal to

r=\frac{1}{4}

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

a_1=40

Therefore, the nth term is calculated as

\:a_n=a_0\cdot r^{n-1}

a_n=40\left(\frac{1}{4}\right)^{n-1}

Put n = 5 to find the next term

a_5=40\left(\frac{1}{4}\right)^{5-1}

a_5=40\cdot \frac{1}{4^4}

a_5=\frac{40}{4^4}

   =\frac{2^3\cdot \:5}{2^8}

a_5=\frac{5}{2^5}

a_5=\frac{5}{32}

now, Put n = 6 to find the 6th term

a_6=40\left(\frac{1}{4}\right)^{6-1}

a_6=40\cdot \frac{1}{4^5}

a_6=\frac{40}{4^5}

    =\frac{2^3\cdot \:5}{2^{10}}

a_6=\frac{5}{2^7}

a_6=\frac{5}{128}

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

  • a_5=\frac{5}{32}
  • a_6=\frac{5}{128}
7 0
3 years ago
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