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jolli1 [7]
3 years ago
11

If f (x)=x^2, then f (4) = 4^2= 16

Mathematics
1 answer:
inn [45]3 years ago
4 0

Answer: t^2

Step-by-step explanation:

if f(x)=x^2

then f(t)=t^2

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Target store is having a 10% off sale on PS5 this
Oduvanchick [21]

Answer:

Step-by-step explanation:

x-10/100x

4 0
3 years ago
What are the next three terms in these 2 sequences?<br><br> 1. 3, 8, 23, 68<br><br> 2. 2, 6, 18
Karolina [17]

1:
3*3=8 ;
8*3=23
23*3=68
68*3=204
1.3,8,23,68,204 ... 

2.
2*3=6
6*3=18
18*3=54
2, 6,18,54


multiply all on 3)

3 0
3 years ago
The decreasing​ population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=−0.
n200080 [17]

By solving a quadratic equation, it can be verified that

The owl population will disappear after 329.12 years

What is a quadratic equation?

At first it is important to know about equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A two degree equation is known as quadratic equation.

Here, a quadratic equation needs to be solved

The decreasing​ population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=-0. 4t^2+128t+1,200

For population to disappear, p =0

-0. 4t^2+128t+1,200 = 0\\0.4t^2 -128t - 1200 = 0\\4t^2 - 1280t - 12000 = 0\\4(t^2 - 320 t - 3000) = 0\\t^2 - 320t -3000 = 0\\t = \frac{-(-320)\pm \sqrt{(-320)^2 - 4 \times 1 \times (-3000)}}{2 \times 1}\\t = \frac{320 \pm 338.23}{2}\\t = \frac{320 + 338.23}{2} \ or \ t = \frac{320 - 338.23}{2}\\t = 329.115 \ or \ t = -9.115

But t = -9.115 is not possible as time cannot be negative

So, the owl population will disappear after 329.12 years

To learn more about quadratic equation, refer to the link-

brainly.com/question/1214333

#SPJ4

7 0
1 year ago
I have 6 one, 7 tens and 14 hundreds. what number am i?​
Lisa [10]

Answer:

Step-by-step explanation:

6×1 = 6

7×10 = 70

14×100 = 1400

6+70+1400 = 1476

6 0
3 years ago
Read 2 more answers
A software company is releasing one of their products on a CD. The manufacturer charges a $9700 setup fee and $1.25 per CD. Appr
Gre4nikov [31]

Answer:

  about 4312

Step-by-step explanation:

You want the total cost for n CDs to be 3.50n.

The manufacturer will charge you 9700+1.25n, so you want these to be equal:

  3.50n = 9700 +1.25n

  2.25n = 9700 . . . . . . . . subtract 1.25n

  n = 9700/2.25 ≈ 4311.111...

Producing 4312 CDs will make the cost per CD slightly less than $3.50.

____

Producing 4311 CDs will make the cost per CD be about $3.500058. Producing 4312 CDs will bring it down to $3.499536.

3 0
3 years ago
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