The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
 area = 19.3138746047 

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / 1.65684 
area = 173.824871442 

 173.824871442 / 19.3138746047 = 9

So, the area would be 9 times larger.

ALSO, looking at the formula
n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.

5 0

3 years ago

The diagram below shows part of the graph of the quadratic function f(x)=a(x-h)(x-k) with the condition h<k. Point P is the m

Valentin [98]

Answer:

see explanation

Step-by-step explanation:

(a)

The zeros are x = 1 and x = 5, thus the factors are (x - 1) and (x - 5)

f(x) = a(x - 1)(x - 5)

To find a substitute (0, 15), the coordinates of the y- intercept into the equation.

15 = a(0 - 1)(0 - 5) = a(- 1)(- 5) = 5a ( divide both sides by 5)

a = 3

Thus h = 1, k = 5, a = 3 and

f(x) = 3(x - 1)(x - 5)

(b)

The axis of symmetry is a vertical line with equation x = c ( c is a constant )

The axis of symmetry passes through the midpoint of the zeros

x = $\frac{1+5}{2}$ = $\frac{6}{2}$ = 3

Equation of axis of symmetry is x = 3

(c)

The axis of symmetry passes through P, with x- coordinate x = 3

Substitute x = 3 into the function for corresponding value of y

f(3) = 3(3 - 1)(3 - 5) = 3(2)(- 2) = - 12

Coordinates of P = (3, - 12 )

6 0

4 years ago

Read 2 more answers

The height, h, in feet of a ball above the ground is given by h = −16t2 + 64t + 80, where t is the time in seconds. How long doe

Gwar [14]

Answer:

t = 5 seconds

Step-by-step explanation:

It is given that, the height h, in feet of a ball above the ground is given by :

$h=-16t^2+64t+80$

Where t is in seconds

We need to find how long does it take the ball to hit the ground? When it hits the ground, its height will be equal to 0. So,

$-16t^2+64t+80=0\\\\t=\dfrac{-64\pm \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=\dfrac{-64+ \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16},\dfrac{-64-\sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=-1\ s\ \text{and}\ t=5\ s$

Neglecting negative time.

It means ball will take 5 seconds to hit the ground.

3 0

3 years ago