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AysviL [449]
3 years ago
14

Mo and Kim are sharing 72 pencils in the ratio 3:5

Mathematics
2 answers:
Sedbober [7]3 years ago
6 0

Answer: Mo gets 27 pencils

Step-by-step explanation:

<u>Given</u>

- There are 72 pencils in total

- Let 3x be the number of pencils Mo gets

- Let 5x be the number of pencils Kim gets

<u>Solve</u>

Given

3x + 5x = 72

Combine like terms

8x = 72

Divide 8 on both sides

8x / 8 = 72 / 8

x = 9

Mo = 3x = 3 ( 9 ) = 27 pencils

Hope this helps!! :)

Please let me know if you have any questions

mrs_skeptik [129]3 years ago
3 0

Step-by-step explanation:

let the ratio of pencils be 3x and 5x.

3x+5x=72

8x=72

X=72/8

X= 9

3x=3×9=27

5x=5×9=45 Answer

27 pencils mo get

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Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
3 years ago
NEED HELP ON ALL OF THESE PLEASE
tangare [24]

Answer:

1) 2670m^2

2) 4718 in^2

3) 4730 ft^2

4) 7900cm^2

5) 11 542mm^2

6) 3740m^2

7) 6374m^2

8) 2824 ft^2

9) 6004mm^2

Step-by-step explanation:

Area of a rectangular prism = 2wl + 2lh + 2hw

Where,

w = width

l = length

h = height

1) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 10m; l = 31m; w = 25m

Area = 2(25m)(31m) + 2(31m)(10m) + 2(10m)(25m)

= 2(775m^2) + 2(310m^2) + 2(250m^2)

= 1550m^2 + 620m^2 + 500m^2

= 2670m^2

2) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 21 in; l = 35 in; w = 29 in

Area = 2(29in)(35in) + 2(35in)(21in) + 2(21in)(29in)

= 2(1015in^2) + 2(735in^2) + 2(609in^2)

= 2030in^2 + 1470in^2 + 1218in^2

= 4718 in^2

3) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 19 ft; l = 39ft; w = 28ft

Area = 2(28ft)(39ft) + 2(39ft)(19ft) + 2(19ft)(28ft)

= 4730 ft^2

4) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 24,cm; l = 49cm; w = 38cm

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6) 3740m^2

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8) 2824 ft^2

9) 6004mm^2

Note : Kindly follow the same process for the remaining questions, you'd get their correct answers. I can't finish up due to time constraints. However, you may send me a direct message for the remaining answers. Thank you.

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Answer:

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Step-by-step explanation:

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