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seropon [69]
3 years ago
6

Find the area of the trapozoid.​

Mathematics
2 answers:
Bad White [126]3 years ago
5 0

Area =

\frac{1} {2} \times sum \: of \: parallel \: sides \:  \times height

=》

\frac{1}{2}  \times (6 + 10) \times 5

=》

\frac{1}{2}  \times 16 \times 5

=》

8 \times 5

=》

40

Area = 40 in²

leva [86]3 years ago
3 0

Answer:40

Step-by-step explanation:To find the area of a trapzoid first add base a to base b then multiply the height then after divide the product by 2 the answer is 40 because the height for the trapzoid is 5 and for base 1 is 6 also base 2 is 10.First add 10+6=16 then muitiply 16x5=80 divide 80 with 2 will give you 40.

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saw5 [17]

Answer:

2.

30-7x4 = 2

3.

80

Step-by-step explanation:

2.

First, do 7x4, which equals 28. Then subtract that from 30, and you get 2.

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Do the parentheses first, 21-6=15. Then 15 divided by 0.2 = 75. 75+5=80.

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2 years ago
6) the circular base of a hemisphere of radius 2 rests on the base of a square pyramid of height 6. the hemisphere is tangent to
Rasek [7]

The length of the square base is thus 2 x 3\sqrt{2}/2 = 3\sqrt{2} = A

<h3>What is hemisphere?</h3>

Consequently, a hemisphere is a 3D geometric object that is made up of half of a sphere, with one side being flat and the other being a bowl-like shape. It is created by precisely cutting a spherical along its diameter, leaving behind two identical hemispheres.

EXPLANATION; Let ABCDE be the pyramid with ABCD as the square base. Let O and M be the center of square ABCD and the midpoint of side AB respectively. Lastly, let the hemisphere be tangent to the triangular face ABE at P.

Notice that triangle EOM has a right angle at O. Since the hemisphere is tangent to the triangular face ABE at P, angle EPO is also 90 degree. Hence, triangle EOM is similar to triangle EPO.

OM/2 = 6/EP

OM = 6/EP x 2

OM = 6\sqrt{6^2 - 2^2} x 2 = 3\sqrt{2}/2}

The length of the square base is thus 2 x 3\sqrt{2}/2 = 3\sqrt{2} = A

To know more about Hemisphere, visit;

brainly.com/question/13625065?referrer=searchResults

#SPJ4

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